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Debug info for pest's problem!



Hi Scott,

 

You're a bloody angel. So much time on moi. I think I took the right steps.

 

Here is the little debug file:

HTTPAPI Ver 1.10 released 2004-09-24                          

                                                             

http_url_post(): entered                                     

http_persist_open(): entered                                 

http_long_ParseURL(): entered                                

(GSKit) Handle is not valid.                                 

ssl_error(1): (GSKit) Handle is not valid.                   

SetError() #29: gsk_sec_soc_open: (GSKit) Handle is not valid.

 

I followed through in debug, the problem manifests in CommSSL_Connect proc of COMMSSLR4 at this call:

 

c                   eval      rc = gsk_secure_soc_open(wkEnvH: wwSSLh)

 

The pointer args were each *NULL, and the rc came back = 1. What am I doing wrong?

 

Thanks,

Peter

 

-----Original Message-----
From: owner-ftpapi@xxxxxxxxxxxxx [mailto:owner-ftpapi@xxxxxxxxxxxxx] On Behalf Of Scott Klement
Sent:
Monday, May 02, 2005 9:49 PM
To: ftpapi@xxxxxxxxxxxxx
Subject: Re: I misspoke

 

Sender: Scott Klement <sk@xxxxxxxxxxxxxxxx>

 

Hi Peter,

 

> Therefore a *NULL value was returned, and the code in the caller

> dictated that efforts come to a halt. There was no specific error msg,

> but I'm telling you this is where things broke down.

 

The HTTP_error() subprocedure returns the "specific error message" that

you don't think exists.

 

When you call HTTP_error() (after HTTP_url_post() returns) what does it

say?

 

> I will try to grasp what you've said below (instructions for creating

> the log), but I've not much to add - this is where the code essentially

> "dies" in my case.

 

The problem is, there are MANY possible reasons for the connection to

fail.  Probably over 100 possibilities.

 

I need to know *WHY* the connection fails, not which subprocedure it fails

in  That's what HTTP_Error() (or the log file, if you want to take it to

the next level) will tell you.

 

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